
This page includes Step-by-Step instructions to Calculate the
Coefficient of Partial Determination by hand.
Two Predictor Variables
We first consider a first-order
multiple regression model with two predictor variables:
![]()
SSE(X1) measures the variation in Y when X1 is included in the model.
SSE(X1, X2) measures the variation in Y when both X1 and X2 are included in the model.
Hence, the relative marginal
reduction in the variation in Y associated with X1 and
X2 is already in the
model is :

This measure is the coefficient
of partial determination between Y and , X2
given that X1 is in the model. We denote this measure by
:

Thus,
measures the
proportionate reduction in the variation in Y remaining after X1 is included in the
model that is gained by also including X2 in the model. In the
following parts, we will measure the proportionate reduction in the variation
in Y (Water Consumption) remaining after X1 (Temperature)
is included in the model that is gained by also including X2
(Time mowing the
grass) in the model.
The coefficient of partial
determination between Y and X1, given that X2
is in the model, is
defined correspondingly:

General Case
The generalization of
coefficients of partial determination to three or more X variables in the model
is immediate. For instance:
| C1 |
C2 |
C3 |
C4 |
C5 |
C6 |
C7 |
C8 |
C9 |
| X1 (Temperature) |
X2
(Time mowing the grass) |
Y (Water
Consumption) |
(Regression X1) |
(Regression X1 ) |
(Regression X1 ) |
(Regression
|
(Regression
|
(Regression
|
| 99 |
1.6 |
48 |
46.70 |
1.30 |
1.6900 |
47.835 |
0.165 |
0.02722 |
| 85 |
1.75 |
27 |
26.40 |
0.60 |
0.3600 |
28.570 |
-1.570 |
2.46490 |
| 97 |
1.75 |
48 |
43.80 |
4.20 |
17.6400 |
46.690 |
1.310 |
1.71610 |
| 75 |
1.85 |
16 |
11.90 |
4.10 |
16.8100 |
14.720 |
1.280 |
1.63840 |
| 92 |
1.15 |
32 |
36.55 |
-4.55 |
20.7025 |
31.640 |
0.360 |
0.12960 |
| 85 |
1.5 |
25 |
26.40 |
-1.40 |
1.9600 |
25.445 |
-0.445 |
0.19802 |
| 83 |
1.25 |
20 |
23.50 |
-3.50 |
12.2500 |
19.300 |
0.700 |
0.49000 |
|
Totals |
SSE(X1) |
71.413 |
6.6642 |
Procedure ![]()
This total
value is the sum of squared error, ![]()
So the
Coefficient of Partial Correlation is: ![]()
Note: The coefficient rY2,1 is positive because the coefficient of X2 is positive.
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