Predictor Coef StDev
T P
Constant -121.655
6.540 -18.60
0.000
Time mow 12.532
1.933 6.48
0.003
Temperat 1.51236
0.06077 24.89
0.000
Model Equation:
Water = - 122 + 1.51*Temperature + 12.5*Mowing Time
Intercept = b(0) = -121.655
Temperature = b(1) = 1.51236
Mowing Time = b(2) = 12.532
StDev=Standard Deviation = s{b(k)}
s{b(0)} = 6.540
s{b(1)} = .06077
s{b(2)} = 1.933
For Testing B(k):
*using your own t-table with 
in each tail and df = (n-p) = (7-4).
For B(0):
t(0) = -121.655
= -18.60 (T)
6.540
P = P-value = .000
Click here for a p-value review.
Conclusion for B(0):
Reject H(0): There is significant evidence to conclude that b(0) should not be dropped from the model.
For B(1):
t(1) = 1.51236
= 24.89 (T)
.06077
P = P-value = .000
Click here for a p-value review.
Conclusion for B(1):
Reject H(0): There is significant evidence to conclude that b(1) should not be dropped from the model.
For B(2):
t(2) = 12.5316
= 6.48 (T)
1.933
P = P-value = .003
Click here for a p-value review.
Conclusion for B(2):
Reject H(0): There is significant evidence to conclude that b(2) should not be dropped from the model.
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